CLEVELAND, Ohio (WOIO) - Myles Garrett has earned AFC Defensive Player of the Month for October, the NFL announced Thursday.
Garrett recorded six sacks, two forced fumbles, 14 tackles and two strip-sacks. He led the NFL in sacks (six) and sack yardage (53.0) in October, while tying for the NFL lead with two strip-sacks. He recorded a sack in every game in October and extended his streak to six consecutive games with at least one sack, a Browns record and the longest active streak in the NFL. Garrett is leading the NFL this season with nine sacks and four strip-sacks and is tied for the league lead with four forced fumbles, while the Browns are leading the NFL with 14 total takeaways.
Garrett helped the Browns to a 3-1 record in the month of October, the team’s best record in the month of October since 2014. The Browns' three wins tied for the most of any NFL team in October this year.
This is the first monthly league award for Garrett, who was previously named AFC Defensive Player of the Week for Week 4 this season. He is the first Brown to earn a monthly award since Jamie Gillan was named AFC Special Teams Player of the Month for September in 2019. Garrett is the first Browns defensive player to earn a monthly award since D’Qwell Jackson was named AFC Defensive Player of the Month for September in 2011.